Write a C program to print all Armstrong numbers between 1 to n

Print all Armstrong numbers between 1 to n

Sample Output

Enter a limit for armstrong numbers: 900

All armstrong numbers 1 to 900: 1 2 3 4 5 6 7 8 9 153 370 371 407

Source Code

#include<stdio.h>
#include<math.h>
 
//Print all Armstrong numbers between 1 to n
 
int main()
{
    int i, limit, number, numberClone, digit, count = 0, newNumber = 0;
 
    printf("Enter a limit for armstrong numbers: ");
    scanf("%d", &limit);
 
    printf("\nAll armstrong numbers 1 to %d: ", limit);
    for(i = 1; i <= limit; i++)
    {
        number = i;
        numberClone = number;
        while(number != 0)
        {
            digit = (number%10);
            number /= 10;
            count++;
        }
 
        number = numberClone;
        while(number != 0)
        {
            digit = (number%10);
            number /= 10;
 
            newNumber += pow(digit, count);
        }
 
        if(numberClone == newNumber)
        {
            printf("%d ", newNumber);
        }
 
        count = 0;
        newNumber = 0;
    }
    printf("\n\n");
 
    return 0;
}

Sample Output

Enter a limit for armstrong numbers: 900

All armstrong numbers 1 to 900: 0 1 2 3 4 5 6 7 8 9 153 370 371 407