Write a C program to count total number of notes in given amount

Count total number of notes in given amount

Sample Output

Count total number of notes in given amount.


Enter your amount: 999
Note of 1000: 0
Note of 500: 1
Note of 100: 4
Note of 50: 1
Note of 20: 2
Note of 10: 0
Note of 5: 1
Note of 2: 2
Note of 1: 0

Process returned 13 (0xD)   execution time : 3.449 s
Press any key to continue.

Source Code

#include<stdio.h>
 
void main()
{
    int amount, note1000, note500, note100, note50, note20, note10, note5, note2, note1;
    
    printf("Count total number of notes in given amount.\n\n");
    
    scanf("%d", &amount, printf("\nEnter your amount: "));
 
    note1000 = amount / 1000;
    amount = amount % 1000;
    printf("Note of 1000: %d\n", note1000);
 
    note500 = amount / 500;
    amount = amount % 500;
    printf("Note of 500: %d\n", note500);
 
    note100 = amount / 100;
    amount = amount % 100;
    printf("Note of 100: %d\n", note100);
 
    note50 = amount / 50;
    amount = amount % 50;
    printf("Note of 50: %d\n", note50);
 
    note20 = amount / 20;
    amount = amount % 20;
     printf("Note of 20: %d\n", note20);
     
    note10 = amount / 10;
    amount = amount % 10;
    printf("Note of 10: %d\n", note10);
 
    note5 = amount / 5;
    amount = amount % 5;
    printf("Note of 5: %d\n", note5);
 
    note2 = amount / 2;
    printf("Note of 2: %d\n", note2);
 
    note1 = amount % 2;
    printf("Note of 1: %d\n", note1);
}

Sample Output

Count total number of notes in given amount.


Enter your amount: 5693
Note of 1000: 5
Note of 500: 1
Note of 100: 1
Note of 50: 1
Note of 20: 2
Note of 10: 0
Note of 5: 0
Note of 2: 1
Note of 1: 1

Process returned 13 (0xD)   execution time : 2.904 s
Press any key to continue.