Generate Unique Random Numbers
Sample Output
Enter a limit of random number: 10 1 5 2 4 9 3 10 6 8 7
Source Code
import java.util.ArrayList;
import java.util.Random;
import java.util.Scanner;
public class Main {
public static boolean isDuplicate(ArrayList<Integer> numbers, int randomNumber){
for (int i = 0; i < numbers.size(); i++) {
if (numbers.get(i) == randomNumber) {
return true;
}
}
return false;
}
public static void main(String args[]) {
Random random = new Random();
int uniqueNumberCount = 0, randomNumber, limit;
ArrayList<Integer> pastNumber = new ArrayList<>();
Scanner in = new Scanner(System.in);
System.out.print("Enter a limit of random number: ");
limit = in.nextInt();
for (int i = 0; uniqueNumberCount < limit; i++) {
randomNumber = random.nextInt(limit) + 1;
if (!isDuplicate(pastNumber, randomNumber)) {
System.out.println(randomNumber);
pastNumber.add(uniqueNumberCount++, randomNumber);
}
}
}
}
Sample Output
Enter a limit of random number: 5 5 4 2 1 3
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