Find frequency of each digit in a given integers
Sample Output
Find frequency of each digit in a given integer. Enter a number: 20221 Frequency of 0 = 1 Frequency of 1 = 1 Frequency of 2 = 3 Frequency of 3 = 0 Frequency of 4 = 0 Frequency of 5 = 0 Frequency of 6 = 0 Frequency of 7 = 0 Frequency of 8 = 0 Frequency of 9 = 0
Java-Source Code
//package loopinjava; import java.util.Scanner; public class Main181 { public static void main(String[] args) { int i, count, digit, freqCount[] = new int[10], number; Scanner input = new Scanner(System.in); System.out.println("Find frequency of each digit in a given integer.\n"); System.out.print("Enter a number: "); number = input.nextInt(); while (number != 0) { digit = (number % 10); number = (number / 10); freqCount[digit]++; } for (i = 0; i <= 9; i++) { /// if(freqCount[i] > 0) /** This line will be print, if frequency is greater than 0.*/ { System.out.println("Frequency of " + i + " = " + freqCount[i]); } } } }
Sample Output
Find frequency of each digit in a given integer. Enter a number: 192004599 Frequency of 0 = 2 Frequency of 1 = 1 Frequency of 2 = 1 Frequency of 3 = 0 Frequency of 4 = 1 Frequency of 5 = 1 Frequency of 6 = 0 Frequency of 7 = 0 Frequency of 8 = 0 Frequency of 9 = 3
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