Find frequency of each digit in a given integers
Sample Output
    Find frequency of each digit in a given integer. Enter a number: 20221 Frequency of 0 = 1 Frequency of 1 = 1 Frequency of 2 = 3 Frequency of 3 = 0 Frequency of 4 = 0 Frequency of 5 = 0 Frequency of 6 = 0 Frequency of 7 = 0 Frequency of 8 = 0 Frequency of 9 = 0
Java-Source Code 
    //package loopinjava;
import java.util.Scanner;
public class Main181 {
    public static void main(String[] args) {
        int i, count, digit, freqCount[] = new int[10], number;
        Scanner input = new Scanner(System.in);
        System.out.println("Find frequency of each digit in a given integer.\n");
        System.out.print("Enter a number: ");
        number = input.nextInt();
        while (number != 0) {
            
            digit = (number % 10);
            number = (number / 10);
            freqCount[digit]++;
        }
        for (i = 0; i <= 9; i++) {
            /// if(freqCount[i] > 0) /** This line will be print, if frequency is greater than 0.*/
            {
                System.out.println("Frequency of " + i + " = " + freqCount[i]);
            }
        }
    }
}
Sample Output
    Find frequency of each digit in a given integer. Enter a number: 192004599 Frequency of 0 = 2 Frequency of 1 = 1 Frequency of 2 = 1 Frequency of 3 = 0 Frequency of 4 = 1 Frequency of 5 = 1 Frequency of 6 = 0 Frequency of 7 = 0 Frequency of 8 = 0 Frequency of 9 = 3
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