Check whether a number is Armstrong number or not
Sample Output
Check whether a number is Armstrong number or not. Enter a number: 371 371 is an Armstrong number!
Java-Source Code
//package loopinjava;
import java.util.Scanner;
import static java.lang.Math.pow;
public class Main {
public static void main(String[] args) {
int i, j, digit, number, numberClone, count = 0, newNumber = 0, temp;
Scanner input = new Scanner(System.in);
System.out.println("Check whether a number is Armstrong number or not.\n");
System.out.print("Enter a number: ");
number = input.nextInt();
numberClone = number;
while (number != 0) {
digit = (number % 10);
number /= 10; /// Or, number = number / 10;
count++;
}
number = numberClone;
while (number != 0) {
digit = (number % 10);
temp = (int) pow(digit, count);
newNumber += temp;
number /= 10; /// Or, number = number / 10;
}
number = numberClone;
if (newNumber == number) {
System.out.println(number + " is an Armstrong number!\n\n");
} else {
System.out.println(number + " is not an Armstrong number.\n\n");
}
}
}
Sample Output
Check whether a number is Armstrong number or not. Enter a number: 372 372 is not an Armstrong number.
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