Check whether a number is Armstrong number or not
Sample Output
    Check whether a number is Armstrong number or not. Enter a number: 371 371 is an Armstrong number!
Java-Source Code 
    //package loopinjava;
import java.util.Scanner;
import static java.lang.Math.pow;
public class Main {
    public static void main(String[] args) {
        int i, j, digit, number, numberClone, count = 0, newNumber = 0, temp;
        Scanner input = new Scanner(System.in);
        System.out.println("Check whether a number is Armstrong number or not.\n");
        System.out.print("Enter a number: ");
        number = input.nextInt();
        numberClone = number;
        
        while (number != 0) {
            digit = (number % 10);
            number /= 10; /// Or, number = number / 10;
            count++;
        }
        number = numberClone;
        while (number != 0) {
            digit = (number % 10);
            temp = (int) pow(digit, count);
            newNumber += temp;
            number /= 10; /// Or, number = number / 10;
        }
        number = numberClone;
        
        if (newNumber == number) {
            
            System.out.println(number + " is an Armstrong number!\n\n");
            
        } else {
            
            System.out.println(number + " is not an Armstrong number.\n\n");
        }
    }
}
Sample Output
    Check whether a number is Armstrong number or not. Enter a number: 372 372 is not an Armstrong number.
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