Java If-Else | HackerRank

Java If-Else

In this challenge, we test your knowledge of using if-else conditional statements to automate decision-making processes. An if-else statement has the following logical flow:

Source: Wikipedia

Task

Given an integer, n, perform the following conditional actions:

• If n is odd, print Weird
• If n is even and in the inclusive range of 2 to 5, print Not Weird
• If n is even and in the inclusive range of 6 to 20, print Weird
• If n is even and greater than 20, print Not Weird

Complete the stub code provided in your editor to print whether or not  is weird.

Input Format

A single line containing a positive integer, n.

Constraints

• 1 <= n <= 100

Output Format

Print Weird if the number is weird; otherwise, print Not Weird.

Sample Input 0

3

Sample Output 0

Weird

Sample Input 1

24

Sample Output 1

Not Weird

Explanation

Sample Case 0: n = 3

n is odd and odd numbers are weird, so we print Weird.

Sample Case 1: n = 24

n > 20 and  is even, so it isn't weird. Thus, we print Not Weird.

Sample Output

3
Weird


...Program finished with exit code 0
Press ENTER to exit console.

Java-Source Code

import java.io.*;
import java.math.*;
import java.security.*;
import java.text.*;
import java.util.*;
import java.util.concurrent.*;
import java.util.regex.*;
 
public class Solution {
 
    private static final Scanner scanner = new Scanner(System.in);
 
    public static void main(String[] args) {
        int N = scanner.nextInt();
        scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");
        if(N%2 == 0){
            if(N >= 2 && N <= 5){
                System.out.println("Not Weird");
            }
            else if(N >= 6 && N <= 20){
                System.out.println("Weird");
            }
            else if(N >= 20){
                System.out.println("Not Weird");
            }
        }
        else{
            System.out.println("Weird");
        }
 
        scanner.close();
    }
}

Sample Output

24
Not Weird


...Program finished with exit code 0
Press ENTER to exit console.

HackerRank